Base | Representation |
---|---|
bin | 10000000001100101110… |
… | …101101100011000011011 |
3 | 10220021102221002110012211 |
4 | 100001211311230120123 |
5 | 121020244332431021 |
6 | 2201521002415551 |
7 | 142363156162546 |
oct | 20014565543033 |
9 | 3807387073184 |
10 | 1101220202011 |
11 | 395030105906 |
12 | 1595105015b7 |
13 | 7cac9823ab7 |
14 | 3b42957585d |
15 | 1d9a2b7c3e1 |
hex | 10065d6c61b |
1101220202011 has 8 divisors (see below), whose sum is σ = 1101576803600. Its totient is φ = 1100863670688.
The previous prime is 1101220202009. The next prime is 1101220202053. The reversal of 1101220202011 is 1102020221011.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1101220202011 - 21 = 1101220202009 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1101220201982 and 1101220202000.
It is not an unprimeable number, because it can be changed into a prime (1101220202111) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 54643765 + ... + 54663913.
It is an arithmetic number, because the mean of its divisors is an integer number (137697100450).
Almost surely, 21101220202011 is an apocalyptic number.
1101220202011 is a deficient number, since it is larger than the sum of its proper divisors (356601589).
1101220202011 is an equidigital number, since it uses as much as digits as its factorization.
1101220202011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 35133.
The product of its (nonzero) digits is 16, while the sum is 13.
Adding to 1101220202011 its reverse (1102020221011), we get a palindrome (2203240423022).
The spelling of 1101220202011 in words is "one trillion, one hundred one billion, two hundred twenty million, two hundred two thousand, eleven".
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