Base | Representation |
---|---|
bin | 11001000010011111001100… |
… | …101001110000010011011011 |
3 | 112102220120101111020102222221 |
4 | 121002133030221300103123 |
5 | 103413220030044444323 |
6 | 1030113221102324511 |
7 | 32124026203426042 |
oct | 3102371451602333 |
9 | 472816344212887 |
10 | 110122099999963 |
11 | 320a757a633377 |
12 | 10426498589737 |
13 | 495a61457664c |
14 | 1d29d1c133559 |
15 | cae7ddc3055d |
hex | 6427cca704db |
110122099999963 has 2 divisors, whose sum is σ = 110122099999964. Its totient is φ = 110122099999962.
The previous prime is 110122099999949. The next prime is 110122100000021. The reversal of 110122099999963 is 369999990221011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 110122099999963 - 229 = 110121563129051 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 110122099999892 and 110122099999901.
It is not a weakly prime, because it can be changed into another prime (110122099993963) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55061049999981 + 55061049999982.
It is an arithmetic number, because the mean of its divisors is an integer number (55061049999982).
Almost surely, 2110122099999963 is an apocalyptic number.
110122099999963 is a deficient number, since it is larger than the sum of its proper divisors (1).
110122099999963 is an equidigital number, since it uses as much as digits as its factorization.
110122099999963 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 38263752, while the sum is 70.
The spelling of 110122099999963 in words is "one hundred ten trillion, one hundred twenty-two billion, ninety-nine million, nine hundred ninety-nine thousand, nine hundred sixty-three".
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