Base | Representation |
---|---|
bin | 1010000000111111101011… |
… | …1011010001000101110011 |
3 | 1102222202102220211202212212 |
4 | 2200033322323101011303 |
5 | 2420411002010121042 |
6 | 35230535004042335 |
7 | 2214414566143211 |
oct | 240177273210563 |
9 | 42882386752785 |
10 | 11012211020147 |
11 | 35662860400a7 |
12 | 129a2a72333ab |
13 | 61b5a7200b6c |
14 | 2a0dcb203cb1 |
15 | 1416bd70e482 |
hex | a03faed1173 |
11012211020147 has 2 divisors, whose sum is σ = 11012211020148. Its totient is φ = 11012211020146.
The previous prime is 11012211020119. The next prime is 11012211020231. The reversal of 11012211020147 is 74102011221011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11012211020147 - 226 = 11012143911283 is a prime.
It is not a weakly prime, because it can be changed into another prime (11012211020747) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506105510073 + 5506105510074.
It is an arithmetic number, because the mean of its divisors is an integer number (5506105510074).
Almost surely, 211012211020147 is an apocalyptic number.
11012211020147 is a deficient number, since it is larger than the sum of its proper divisors (1).
11012211020147 is an equidigital number, since it uses as much as digits as its factorization.
11012211020147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 224, while the sum is 23.
Adding to 11012211020147 its reverse (74102011221011), we get a palindrome (85114222241158).
The spelling of 11012211020147 in words is "eleven trillion, twelve billion, two hundred eleven million, twenty thousand, one hundred forty-seven".
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