11012300113 has 4 divisors (see below), whose sum is σ = 11025120880. Its totient is φ = 10999479348.

The previous prime is 11012300107. The next prime is 11012300119. The reversal of 11012300113 is 31100321011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31100321011 = 85889 ⋅362099.

It is an interprime number because it is at equal distance from previous prime (11012300107) and next prime (11012300119).

It is a cyclic number.

It is not a de Polignac number, because 11012300113 - 2⁵ = 11012300081 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11012300093 and 11012300102.

It is not an unprimeable number, because it can be changed into a prime (11012300119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6409095 + ... + 6410812.

It is an arithmetic number, because the mean of its divisors is an integer number (2756280220).

Almost surely, 2^11012300113 is an apocalyptic number.

It is an amenable number.

11012300113 is a deficient number, since it is larger than the sum of its proper divisors (12820767).

11012300113 is an equidigital number, since it uses as much as digits as its factorization.

11012300113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12820766.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 11012300113 its reverse (31100321011), we get a palindrome (42112621124).

The spelling of 11012300113 in words is "eleven billion, twelve million, three hundred thousand, one hundred thirteen".