Base | Representation |
---|---|
bin | 1010000001000000000001… |
… | …1000010100111001101101 |
3 | 1102222202200022000122120221 |
4 | 2200100000120110321231 |
5 | 2420411143421232023 |
6 | 35230552033211341 |
7 | 2214420060001300 |
oct | 240200030247155 |
9 | 42882608018527 |
10 | 11012302524013 |
11 | 356632275932a |
12 | 129a311a00b51 |
13 | 61b5c015b46b |
14 | 2a0dd9422b37 |
15 | 1416c678685d |
hex | a0400614e6d |
11012302524013 has 12 divisors (see below), whose sum is σ = 13001426925312. Its totient is φ = 9298234111320.
The previous prime is 11012302524011. The next prime is 11012302524037. The reversal of 11012302524013 is 31042520321011.
It is not a de Polignac number, because 11012302524013 - 21 = 11012302524011 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11012302524011) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1677167373 + ... + 1677173938.
It is an arithmetic number, because the mean of its divisors is an integer number (1083452243776).
Almost surely, 211012302524013 is an apocalyptic number.
It is an amenable number.
11012302524013 is a deficient number, since it is larger than the sum of its proper divisors (1989124401299).
11012302524013 is an equidigital number, since it uses as much as digits as its factorization.
11012302524013 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3354341392 (or 3354341385 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 11012302524013 its reverse (31042520321011), we get a palindrome (42054822845024).
The spelling of 11012302524013 in words is "eleven trillion, twelve billion, three hundred two million, five hundred twenty-four thousand, thirteen".
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