Base | Representation |
---|---|
bin | 1010000001000000000001… |
… | …1000010110011101010111 |
3 | 1102222202200022000222100011 |
4 | 2200100000120112131113 |
5 | 2420411143421433031 |
6 | 35230552033301051 |
7 | 2214420060026011 |
oct | 240200030263527 |
9 | 42882608028304 |
10 | 11012302530391 |
11 | 35663227630a8 |
12 | 129a311a04787 |
13 | 61b5c0161336 |
14 | 2a0dd94251b1 |
15 | 1416c67886b1 |
hex | a0400616757 |
11012302530391 has 2 divisors, whose sum is σ = 11012302530392. Its totient is φ = 11012302530390.
The previous prime is 11012302530241. The next prime is 11012302530451. The reversal of 11012302530391 is 19303520321011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11012302530391 - 231 = 11010155046743 is a prime.
It is a super-2 number, since 2×110123025303912 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11012302539391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506151265195 + 5506151265196.
It is an arithmetic number, because the mean of its divisors is an integer number (5506151265196).
Almost surely, 211012302530391 is an apocalyptic number.
11012302530391 is a deficient number, since it is larger than the sum of its proper divisors (1).
11012302530391 is an equidigital number, since it uses as much as digits as its factorization.
11012302530391 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4860, while the sum is 31.
The spelling of 11012302530391 in words is "eleven trillion, twelve billion, three hundred two million, five hundred thirty thousand, three hundred ninety-one".
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