Base | Representation |
---|---|
bin | 1010000001000000001000… |
… | …0110111111101100101111 |
3 | 1102222202202022121120101112 |
4 | 2200100002012333230233 |
5 | 2420411223333111101 |
6 | 35230554551102235 |
7 | 2214420561411002 |
oct | 240200206775457 |
9 | 42882668546345 |
10 | 11012331535151 |
11 | 3566338073881 |
12 | 129a31b67197b |
13 | 61b5c617830b |
14 | 2a0ddd215539 |
15 | 1416c90b76bb |
hex | a04021bfb2f |
11012331535151 has 2 divisors, whose sum is σ = 11012331535152. Its totient is φ = 11012331535150.
The previous prime is 11012331535111. The next prime is 11012331535199. The reversal of 11012331535151 is 15153513321011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11012331535151 - 214 = 11012331518767 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11012331535111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506165767575 + 5506165767576.
It is an arithmetic number, because the mean of its divisors is an integer number (5506165767576).
Almost surely, 211012331535151 is an apocalyptic number.
11012331535151 is a deficient number, since it is larger than the sum of its proper divisors (1).
11012331535151 is an equidigital number, since it uses as much as digits as its factorization.
11012331535151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6750, while the sum is 32.
Adding to 11012331535151 its reverse (15153513321011), we get a palindrome (26165844856162).
The spelling of 11012331535151 in words is "eleven trillion, twelve billion, three hundred thirty-one million, five hundred thirty-five thousand, one hundred fifty-one".
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