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1101240204013 is a prime number
BaseRepresentation
bin10000000001100111000…
…001111111101011101101
310220021111022201122210201
4100001213001333223231
5121020314443012023
62201522555233501
7142363521200455
oct20014701775355
93807438648721
101101240204013
11395040427694
12159517148891
137cb00a080c1
143b42c0a0d65
151d9a47cdbad
hex1006707faed

1101240204013 has 2 divisors, whose sum is σ = 1101240204014. Its totient is φ = 1101240204012.

The previous prime is 1101240204007. The next prime is 1101240204037. The reversal of 1101240204013 is 3104020421011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1032879918249 + 68360285764 = 1016307^2 + 261458^2 .

It is an emirp because it is prime and its reverse (3104020421011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1101240204013 - 213 = 1101240195821 is a prime.

It is a super-2 number, since 2×11012402040132 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1101240204313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550620102006 + 550620102007.

It is an arithmetic number, because the mean of its divisors is an integer number (550620102007).

Almost surely, 21101240204013 is an apocalyptic number.

It is an amenable number.

1101240204013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1101240204013 is an equidigital number, since it uses as much as digits as its factorization.

1101240204013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 1101240204013 its reverse (3104020421011), we get a palindrome (4205260625024).

The spelling of 1101240204013 in words is "one trillion, one hundred one billion, two hundred forty million, two hundred four thousand, thirteen".