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11013000103 = 71573285729
BaseRepresentation
bin10100100000110110…
…10000101110100111
31001102111220101000201
422100123100232213
5140023312000403
65020450451331
7536624646010
oct122033205647
931374811021
1011013000103
114741607a86
122174293b47
131066829911
147668d6007
15446cab21d
hex2906d0ba7

11013000103 has 4 divisors (see below), whose sum is σ = 12586285840. Its totient is φ = 9439714368.

The previous prime is 11013000073. The next prime is 11013000133. The reversal of 11013000103 is 30100031011.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (11013000073) and next prime (11013000133).

It is not a de Polignac number, because 11013000103 - 233 = 2423065511 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11013000103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11013000133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 786642858 + ... + 786642871.

It is an arithmetic number, because the mean of its divisors is an integer number (3146571460).

Almost surely, 211013000103 is an apocalyptic number.

11013000103 is a deficient number, since it is larger than the sum of its proper divisors (1573285737).

11013000103 is an equidigital number, since it uses as much as digits as its factorization.

11013000103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1573285736.

The product of its (nonzero) digits is 9, while the sum is 10.

Adding to 11013000103 its reverse (30100031011), we get a palindrome (41113031114).

The spelling of 11013000103 in words is "eleven billion, thirteen million, one hundred three", and thus it is an aban number.

Divisors: 1 7 1573285729 11013000103