Base | Representation |
---|---|
bin | 10000000001101010100… |
… | …110100001111110110010 |
3 | 10220021122111110100221022 |
4 | 100001222212201332302 |
5 | 121020430312111310 |
6 | 2201532535255442 |
7 | 142365146336264 |
oct | 20015246417662 |
9 | 3807574410838 |
10 | 1101300113330 |
11 | 39507122641a |
12 | 15953321a582 |
13 | 7cb102529c1 |
14 | 3b436017b34 |
15 | 1d9a9bb4a55 |
hex | 1006a9a1fb2 |
1101300113330 has 32 divisors (see below), whose sum is σ = 2004852605184. Its totient is φ = 435531249216.
The previous prime is 1101300113327. The next prime is 1101300113351. The reversal of 1101300113330 is 333110031011.
It is a junction number, because it is equal to n+sod(n) for n = 1101300113299 and 1101300113308.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 240734 + ... + 1503513.
It is an arithmetic number, because the mean of its divisors is an integer number (62651643912).
Almost surely, 21101300113330 is an apocalyptic number.
1101300113330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1101300113330 is a deficient number, since it is larger than the sum of its proper divisors (903552491854).
1101300113330 is a wasteful number, since it uses less digits than its factorization.
1101300113330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1744970.
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 1101300113330 its reverse (333110031011), we get a palindrome (1434410144341).
The spelling of 1101300113330 in words is "one trillion, one hundred one billion, three hundred million, one hundred thirteen thousand, three hundred thirty".
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