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1101300113330 = 251036131744247
BaseRepresentation
bin10000000001101010100…
…110100001111110110010
310220021122111110100221022
4100001222212201332302
5121020430312111310
62201532535255442
7142365146336264
oct20015246417662
93807574410838
101101300113330
1139507122641a
1215953321a582
137cb102529c1
143b436017b34
151d9a9bb4a55
hex1006a9a1fb2

1101300113330 has 32 divisors (see below), whose sum is σ = 2004852605184. Its totient is φ = 435531249216.

The previous prime is 1101300113327. The next prime is 1101300113351. The reversal of 1101300113330 is 333110031011.

It is a junction number, because it is equal to n+sod(n) for n = 1101300113299 and 1101300113308.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 240734 + ... + 1503513.

It is an arithmetic number, because the mean of its divisors is an integer number (62651643912).

Almost surely, 21101300113330 is an apocalyptic number.

1101300113330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1101300113330 is a deficient number, since it is larger than the sum of its proper divisors (903552491854).

1101300113330 is a wasteful number, since it uses less digits than its factorization.

1101300113330 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1744970.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 1101300113330 its reverse (333110031011), we get a palindrome (1434410144341).

The spelling of 1101300113330 in words is "one trillion, one hundred one billion, three hundred million, one hundred thirteen thousand, three hundred thirty".

Divisors: 1 2 5 10 103 206 515 613 1030 1226 3065 6130 63139 126278 315695 631390 1744247 3488494 8721235 17442470 179657441 359314882 898287205 1069223411 1796574410 2138446822 5346117055 10692234110 110130011333 220260022666 550650056665 1101300113330