Base | Representation |
---|---|
bin | 1010000001000010101000… |
… | …0010000001011100001011 |
3 | 1102222211110222221011202022 |
4 | 2200100222002001130023 |
5 | 2420414111314221303 |
6 | 35231145234555055 |
7 | 2214443303450051 |
oct | 240205202013413 |
9 | 42884428834668 |
10 | 11013001320203 |
11 | 3566651156243 |
12 | 129a487a38a8b |
13 | 61b6a1b6892c |
14 | 2a10641661d1 |
15 | 141717cbc438 |
hex | a042a08170b |
11013001320203 has 2 divisors, whose sum is σ = 11013001320204. Its totient is φ = 11013001320202.
The previous prime is 11013001320179. The next prime is 11013001320253. The reversal of 11013001320203 is 30202310031011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11013001320203 - 210 = 11013001319179 is a prime.
It is a super-2 number, since 2×110130013202032 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11013001320253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506500660101 + 5506500660102.
It is an arithmetic number, because the mean of its divisors is an integer number (5506500660102).
Almost surely, 211013001320203 is an apocalyptic number.
11013001320203 is a deficient number, since it is larger than the sum of its proper divisors (1).
11013001320203 is an equidigital number, since it uses as much as digits as its factorization.
11013001320203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 11013001320203 its reverse (30202310031011), we get a palindrome (41215311351214).
The spelling of 11013001320203 in words is "eleven trillion, thirteen billion, one million, three hundred twenty thousand, two hundred three".
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