Base | Representation |
---|---|
bin | 11001000010100110100101… |
… | …010110000000001101011011 |
3 | 112102221022212011202210222102 |
4 | 121002212211112000031123 |
5 | 103413332300243223103 |
6 | 1030121012035314015 |
7 | 32124426551206163 |
oct | 3102464526001533 |
9 | 472838764683872 |
10 | 110130030445403 |
11 | 320aa97a114411 |
12 | 10427b3044b90b |
13 | 495b2a9575907 |
14 | 1d2a4714935a3 |
15 | caeb0508be88 |
hex | 6429a558035b |
110130030445403 has 2 divisors, whose sum is σ = 110130030445404. Its totient is φ = 110130030445402.
The previous prime is 110130030445301. The next prime is 110130030445529. The reversal of 110130030445403 is 304544030031011.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 110130030445403 - 218 = 110130030183259 is a prime.
It is not a weakly prime, because it can be changed into another prime (110130030445703) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55065015222701 + 55065015222702.
It is an arithmetic number, because the mean of its divisors is an integer number (55065015222702).
Almost surely, 2110130030445403 is an apocalyptic number.
110130030445403 is a deficient number, since it is larger than the sum of its proper divisors (1).
110130030445403 is an equidigital number, since it uses as much as digits as its factorization.
110130030445403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 110130030445403 its reverse (304544030031011), we get a palindrome (414674060476414).
The spelling of 110130030445403 in words is "one hundred ten trillion, one hundred thirty billion, thirty million, four hundred forty-five thousand, four hundred three".
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