11013103313 has 4 divisors (see below), whose sum is σ = 11080668528. Its totient is φ = 10945538100.

The previous prime is 11013103303. The next prime is 11013103331. The reversal of 11013103313 is 31330131011.

11013103313 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31330131011 = 17 ⋅1842948883.

It is a cyclic number.

It is not a de Polignac number, because 11013103313 - 2¹² = 11013099217 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11013103291 and 11013103300.

It is not an unprimeable number, because it can be changed into a prime (11013103303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33782363 + ... + 33782688.

It is an arithmetic number, because the mean of its divisors is an integer number (2770167132).

Almost surely, 2^11013103313 is an apocalyptic number.

It is an amenable number.

11013103313 is a deficient number, since it is larger than the sum of its proper divisors (67565215).

11013103313 is an equidigital number, since it uses as much as digits as its factorization.

11013103313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 67565214.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 11013103313 its reverse (31330131011), we get a palindrome (42343234324).

The spelling of 11013103313 in words is "eleven billion, thirteen million, one hundred three thousand, three hundred thirteen".