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11013130023300 = 22325253263877883
BaseRepresentation
bin1010000001000011000110…
…1100111111000110000100
31102222211210222002222012200
42200100301230333012010
52420414342241221200
635231210113314500
72214446425426536
oct240206154770604
942884728088180
1011013130023300
113566707871839
12129a502b65a30
1361b6c271c002
142a10772a9856
15141724241800
hexa0431b3f184

11013130023300 has 216 divisors, whose sum is σ = 35305137451584. Its totient is φ = 2870463448320.

The previous prime is 11013130023257. The next prime is 11013130023323. The reversal of 11013130023300 is 332003131011.

It is a happy number.

11013130023300 is a `hidden beast` number, since 1 + 1 + 0 + 1 + 31 + 300 + 2 + 330 + 0 = 666.

It is a super-2 number, since 2×110131300233002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 12106159 + ... + 12984041.

It is an arithmetic number, because the mean of its divisors is an integer number (163449710424).

Almost surely, 211013130023300 is an apocalyptic number.

11013130023300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11013130023300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17652568725792).

11013130023300 is an abundant number, since it is smaller than the sum of its proper divisors (24292007428284).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11013130023300 is a wasteful number, since it uses less digits than its factorization.

11013130023300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 878219 (or 878209 counting only the distinct ones).

The product of its (nonzero) digits is 162, while the sum is 18.

Adding to 11013130023300 its reverse (332003131011), we get a palindrome (11345133154311).

The spelling of 11013130023300 in words is "eleven trillion, thirteen billion, one hundred thirty million, twenty-three thousand, three hundred".