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1101313132103 = 5496232003761
BaseRepresentation
bin10000000001101011011…
…000001100011001000111
310220021200101221210100002
4100001223120030121013
5121020442130211403
62201534122311515
7142365365111012
oct20015330143107
93807611853302
101101313132103
11395078608638
1215953765859b
137cb12b60612
143b437a46379
151d9aadd7188
hex1006b60c647

1101313132103 has 4 divisors (see below), whose sum is σ = 1101315685488. Its totient is φ = 1101310578720.

The previous prime is 1101313132069. The next prime is 1101313132133. The reversal of 1101313132103 is 3012313131011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1101313132103 - 26 = 1101313132039 is a prime.

It is a super-2 number, since 2×11013131321032 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1101313132133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 452258 + ... + 1551503.

It is an arithmetic number, because the mean of its divisors is an integer number (275328921372).

Almost surely, 21101313132103 is an apocalyptic number.

1101313132103 is a deficient number, since it is larger than the sum of its proper divisors (2553385).

1101313132103 is an equidigital number, since it uses as much as digits as its factorization.

1101313132103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2553384.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 1101313132103 its reverse (3012313131011), we get a palindrome (4113626263114).

The spelling of 1101313132103 in words is "one trillion, one hundred one billion, three hundred thirteen million, one hundred thirty-two thousand, one hundred three".

Divisors: 1 549623 2003761 1101313132103