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1101313425551 = 2937976325019
BaseRepresentation
bin10000000001101011011…
…001010100000010001111
310220021200102111200212112
4100001223121110002033
5121020442214104201
62201534132454235
7142365400442363
oct20015331240217
93807612450775
101101313425551
11395078799059
1215953777a37b
137cb12c34061
143b437ac12a3
151d9aae440bb
hex1006b65408f

1101313425551 has 4 divisors (see below), whose sum is σ = 1139289750600. Its totient is φ = 1063337100504.

The previous prime is 1101313425503. The next prime is 1101313425587. The reversal of 1101313425551 is 1555243131011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1101313425551 - 214 = 1101313409167 is a prime.

It is a super-2 number, since 2×11013134255512 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1101313415551) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18988162481 + ... + 18988162538.

It is an arithmetic number, because the mean of its divisors is an integer number (284822437650).

Almost surely, 21101313425551 is an apocalyptic number.

1101313425551 is a deficient number, since it is larger than the sum of its proper divisors (37976325049).

1101313425551 is an equidigital number, since it uses as much as digits as its factorization.

1101313425551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 37976325048.

The product of its (nonzero) digits is 9000, while the sum is 32.

Adding to 1101313425551 its reverse (1555243131011), we get a palindrome (2656556556562).

The spelling of 1101313425551 in words is "one trillion, one hundred one billion, three hundred thirteen million, four hundred twenty-five thousand, five hundred fifty-one".

Divisors: 1 29 37976325019 1101313425551