1101313441453 has 4 divisors (see below), whose sum is σ = 1101322692288. Its totient is φ = 1101304190620.

The previous prime is 1101313441429. The next prime is 1101313441463. The reversal of 1101313441453 is 3541443131011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1101313441453 - 2¹⁷ = 1101313310381 is a prime.

It is a Smith number, since the sum of its digits (31) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1101313441463) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4444483 + ... + 4685728.

It is an arithmetic number, because the mean of its divisors is an integer number (275330673072).

Almost surely, 2^{1101313441453} is an apocalyptic number.

It is an amenable number.

1101313441453 is a deficient number, since it is larger than the sum of its proper divisors (9250835).

1101313441453 is an equidigital number, since it uses as much as digits as its factorization.

1101313441453 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9250834.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 1101313441453 its reverse (3541443131011), we get a palindrome (4642756572464).

The spelling of 1101313441453 in words is "one trillion, one hundred one billion, three hundred thirteen million, four hundred forty-one thousand, four hundred fifty-three".