Base | Representation |
---|---|
bin | 1010000001000011010111… |
… | …1000010100011011011011 |
3 | 1102222211222211222101122222 |
4 | 2200100311320110123123 |
5 | 2420420013211300011 |
6 | 35231221055334255 |
7 | 2214451236205112 |
oct | 240206570243333 |
9 | 42884884871588 |
10 | 11013200103131 |
11 | 3566743387856 |
12 | 129a52252138b |
13 | 61b7040b7c75 |
14 | 2a108270cc79 |
15 | 14172a485ddb |
hex | a0435e146db |
11013200103131 has 4 divisors (see below), whose sum is σ = 11013225849600. Its totient is φ = 11013174356664.
The previous prime is 11013200103083. The next prime is 11013200103149. The reversal of 11013200103131 is 13130100231011.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11013200103131 - 230 = 11012126361307 is a prime.
It is a super-2 number, since 2×110132001031312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11013200103161) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12220571 + ... + 13090788.
It is an arithmetic number, because the mean of its divisors is an integer number (2753306462400).
Almost surely, 211013200103131 is an apocalyptic number.
11013200103131 is a deficient number, since it is larger than the sum of its proper divisors (25746469).
11013200103131 is an equidigital number, since it uses as much as digits as its factorization.
11013200103131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25746468.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 11013200103131 its reverse (13130100231011), we get a palindrome (24143300334142).
The spelling of 11013200103131 in words is "eleven trillion, thirteen billion, two hundred million, one hundred three thousand, one hundred thirty-one".
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