Base | Representation |
---|---|
bin | 110011010010001100… |
… | …0010110101011111111 |
3 | 101112021021211210202202 |
4 | 1212210120112223333 |
5 | 3301022244431312 |
6 | 122332143342115 |
7 | 10646113545113 |
oct | 1464430265377 |
9 | 345237753682 |
10 | 110132030207 |
11 | 42785729391 |
12 | 19416bb193b |
13 | a5019767a4 |
14 | 548a951743 |
15 | 2ce89c79c2 |
hex | 19a4616aff |
110132030207 has 2 divisors, whose sum is σ = 110132030208. Its totient is φ = 110132030206.
The previous prime is 110132030191. The next prime is 110132030219. The reversal of 110132030207 is 702030231011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 110132030207 - 24 = 110132030191 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110132039207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55066015103 + 55066015104.
It is an arithmetic number, because the mean of its divisors is an integer number (55066015104).
Almost surely, 2110132030207 is an apocalyptic number.
110132030207 is a deficient number, since it is larger than the sum of its proper divisors (1).
110132030207 is an equidigital number, since it uses as much as digits as its factorization.
110132030207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 252, while the sum is 20.
Adding to 110132030207 its reverse (702030231011), we get a palindrome (812162261218).
The spelling of 110132030207 in words is "one hundred ten billion, one hundred thirty-two million, thirty thousand, two hundred seven".
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