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110133021401041 = 313552678109711
BaseRepresentation
bin11001000010101001010111…
…100111100101111111010001
3112102221121120121210002210011
4121002221113213211333101
5103413404411434313131
61030122224522034521
732124563640002362
oct3102512747457721
9472847517702704
10110133021401041
1132101174467681
1210428626048a41
13495b665111552
141d2a6767c3b69
15caec2c9460b1
hex642a579e5fd1

110133021401041 has 4 divisors (see below), whose sum is σ = 113685699510784. Its totient is φ = 106580343291300.

The previous prime is 110133021401033. The next prime is 110133021401059. The reversal of 110133021401041 is 140104120331011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 110133021401041 - 23 = 110133021401033 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (110133021401071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1776339054825 + ... + 1776339054886.

It is an arithmetic number, because the mean of its divisors is an integer number (28421424877696).

Almost surely, 2110133021401041 is an apocalyptic number.

It is an amenable number.

110133021401041 is a deficient number, since it is larger than the sum of its proper divisors (3552678109743).

110133021401041 is an equidigital number, since it uses as much as digits as its factorization.

110133021401041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3552678109742.

The product of its (nonzero) digits is 288, while the sum is 22.

Adding to 110133021401041 its reverse (140104120331011), we get a palindrome (250237141732052).

The spelling of 110133021401041 in words is "one hundred ten trillion, one hundred thirty-three billion, twenty-one million, four hundred one thousand, forty-one".

Divisors: 1 31 3552678109711 110133021401041