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110133130003 = 1331557349037
BaseRepresentation
bin110011010010001110…
…0100011001100010011
3101112021100220200101221
41212210130203030103
53301023040130003
6122332223105511
710646126105401
oct1464434431423
9345240820357
10110133130003
114278630a706
1219417442297
13a501c70260
14548ab5a471
152ce8b437bd
hex19a4723313

110133130003 has 16 divisors (see below), whose sum is σ = 122455339776. Its totient is φ = 98362293120.

The previous prime is 110133130001. The next prime is 110133130043. The reversal of 110133130003 is 300031331011.

It is not a de Polignac number, because 110133130003 - 21 = 110133130001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (110133130001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2221401 + ... + 2270437.

It is an arithmetic number, because the mean of its divisors is an integer number (7653458736).

Almost surely, 2110133130003 is an apocalyptic number.

110133130003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

110133130003 is a deficient number, since it is larger than the sum of its proper divisors (12322209773).

110133130003 is a wasteful number, since it uses less digits than its factorization.

110133130003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 54654.

The product of its (nonzero) digits is 81, while the sum is 16.

Adding to 110133130003 its reverse (300031331011), we get a palindrome (410164461014).

The spelling of 110133130003 in words is "one hundred ten billion, one hundred thirty-three million, one hundred thirty thousand, three".

Divisors: 1 13 31 403 5573 49037 72449 172763 637481 1520147 2245919 19761911 273283201 3552681613 8471779231 110133130003