Base | Representation |
---|---|
bin | 110011010010001110… |
… | …0100011001100010011 |
3 | 101112021100220200101221 |
4 | 1212210130203030103 |
5 | 3301023040130003 |
6 | 122332223105511 |
7 | 10646126105401 |
oct | 1464434431423 |
9 | 345240820357 |
10 | 110133130003 |
11 | 4278630a706 |
12 | 19417442297 |
13 | a501c70260 |
14 | 548ab5a471 |
15 | 2ce8b437bd |
hex | 19a4723313 |
110133130003 has 16 divisors (see below), whose sum is σ = 122455339776. Its totient is φ = 98362293120.
The previous prime is 110133130001. The next prime is 110133130043. The reversal of 110133130003 is 300031331011.
It is not a de Polignac number, because 110133130003 - 21 = 110133130001 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (110133130001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2221401 + ... + 2270437.
It is an arithmetic number, because the mean of its divisors is an integer number (7653458736).
Almost surely, 2110133130003 is an apocalyptic number.
110133130003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
110133130003 is a deficient number, since it is larger than the sum of its proper divisors (12322209773).
110133130003 is a wasteful number, since it uses less digits than its factorization.
110133130003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 54654.
The product of its (nonzero) digits is 81, while the sum is 16.
Adding to 110133130003 its reverse (300031331011), we get a palindrome (410164461014).
The spelling of 110133130003 in words is "one hundred ten billion, one hundred thirty-three million, one hundred thirty thousand, three".
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