Base | Representation |
---|---|
bin | 1010000001000011110011… |
… | …0010111110101110111111 |
3 | 1102222212021221022212220021 |
4 | 2200100330302332232333 |
5 | 2420420232413102223 |
6 | 35231240402433011 |
7 | 2214454145426632 |
oct | 240207462765677 |
9 | 42885257285807 |
10 | 11013316144063 |
11 | 35667a2935052 |
12 | 129a555362767 |
13 | 61b722156b3c |
14 | 2a1093cb7c19 |
15 | 14173575865d |
hex | a043ccbebbf |
11013316144063 has 2 divisors, whose sum is σ = 11013316144064. Its totient is φ = 11013316144062.
The previous prime is 11013316144001. The next prime is 11013316144067. The reversal of 11013316144063 is 36044161331011.
It is a strong prime.
It is an emirp because it is prime and its reverse (36044161331011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11013316144063 - 217 = 11013316012991 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11013316144067) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506658072031 + 5506658072032.
It is an arithmetic number, because the mean of its divisors is an integer number (5506658072032).
Almost surely, 211013316144063 is an apocalyptic number.
11013316144063 is a deficient number, since it is larger than the sum of its proper divisors (1).
11013316144063 is an equidigital number, since it uses as much as digits as its factorization.
11013316144063 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 34.
Adding to 11013316144063 its reverse (36044161331011), we get a palindrome (47057477475074).
The spelling of 11013316144063 in words is "eleven trillion, thirteen billion, three hundred sixteen million, one hundred forty-four thousand, sixty-three".
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