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110133254381 is a prime number
BaseRepresentation
bin110011010010001110…
…1000001100011101101
3101112021101011000000112
41212210131001203231
53301023103120011
6122332225505405
710646130134123
oct1464435014355
9345241130015
10110133254381
11427863950a7
12194174a2265
13a501cb4a57
14548ab8d913
152ce8b6a58b
hex19a47418ed

110133254381 has 2 divisors, whose sum is σ = 110133254382. Its totient is φ = 110133254380.

The previous prime is 110133254249. The next prime is 110133254419. The reversal of 110133254381 is 183452331011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 106253833156 + 3879421225 = 325966^2 + 62285^2 .

It is an emirp because it is prime and its reverse (183452331011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 110133254381 - 210 = 110133253357 is a prime.

It is a super-2 number, since 2×1101332543812 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110133254681) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55066627190 + 55066627191.

It is an arithmetic number, because the mean of its divisors is an integer number (55066627191).

Almost surely, 2110133254381 is an apocalyptic number.

It is an amenable number.

110133254381 is a deficient number, since it is larger than the sum of its proper divisors (1).

110133254381 is an equidigital number, since it uses as much as digits as its factorization.

110133254381 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8640, while the sum is 32.

Adding to 110133254381 its reverse (183452331011), we get a palindrome (293585585392).

The spelling of 110133254381 in words is "one hundred ten billion, one hundred thirty-three million, two hundred fifty-four thousand, three hundred eighty-one".