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11013342314124 = 2231270372248959
BaseRepresentation
bin1010000001000011111001…
…0110110011111010001100
31102222212100202120110110210
42200100332112303322030
52420420311113022444
635231243135402420
72214454614034323
oct240207626637214
942885322513423
1011013342314124
113566806689aa7
12129a562083410
1361b7276ba797
142a109756b0ba
15141737bc77b9
hexa043e5b3e8c

11013342314124 has 24 divisors (see below), whose sum is σ = 25699822059520. Its totient is φ = 3670825058064.

The previous prime is 11013342314123. The next prime is 11013342314137. The reversal of 11013342314124 is 42141324331011.

It is a junction number, because it is equal to n+sod(n) for n = 11013342314091 and 11013342314100.

It is not an unprimeable number, because it can be changed into a prime (11013342314123) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 35972044 + ... + 36276915.

Almost surely, 211013342314124 is an apocalyptic number.

It is an amenable number.

11013342314124 is an abundant number, since it is smaller than the sum of its proper divisors (14686479745396).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11013342314124 is a wasteful number, since it uses less digits than its factorization.

11013342314124 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 72261669 (or 72261667 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 30.

Adding to 11013342314124 its reverse (42141324331011), we get a palindrome (53154666645135).

The spelling of 11013342314124 in words is "eleven trillion, thirteen billion, three hundred forty-two million, three hundred fourteen thousand, one hundred twenty-four".

Divisors: 1 2 3 4 6 12 12703 25406 38109 50812 76218 152436 72248959 144497918 216746877 288995836 433493754 866987508 917778526177 1835557052354 2753335578531 3671114104708 5506671157062 11013342314124