Base | Representation |
---|---|
bin | 1010000001000100001000… |
… | …0111101011010010100111 |
3 | 1102222212112011101101012021 |
4 | 2200101002013223102213 |
5 | 2420420423244034102 |
6 | 35231253313004011 |
7 | 2214456311524126 |
oct | 240210207532247 |
9 | 42885464341167 |
10 | 11013405455527 |
11 | 3566839296082 |
12 | 129a57b253607 |
13 | 61b7377c7567 |
14 | 2a10a1ac5abd |
15 | 14173d4eb137 |
hex | a04421eb4a7 |
11013405455527 has 2 divisors, whose sum is σ = 11013405455528. Its totient is φ = 11013405455526.
The previous prime is 11013405455431. The next prime is 11013405455531. The reversal of 11013405455527 is 72555450431011.
It is a strong prime.
It is an emirp because it is prime and its reverse (72555450431011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11013405455527 - 27 = 11013405455399 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11013405455627) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506702727763 + 5506702727764.
It is an arithmetic number, because the mean of its divisors is an integer number (5506702727764).
Almost surely, 211013405455527 is an apocalyptic number.
11013405455527 is a deficient number, since it is larger than the sum of its proper divisors (1).
11013405455527 is an equidigital number, since it uses as much as digits as its factorization.
11013405455527 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 420000, while the sum is 43.
Adding to 11013405455527 its reverse (72555450431011), we get a palindrome (83568855886538).
The spelling of 11013405455527 in words is "eleven trillion, thirteen billion, four hundred five million, four hundred fifty-five thousand, five hundred twenty-seven".
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