Base | Representation |
---|---|
bin | 1010000001000100100001… |
… | …1011001100011001011010 |
3 | 1102222212210112102112120112 |
4 | 2200101020123030121122 |
5 | 2420421132334011122 |
6 | 35231312012124322 |
7 | 2214462034610432 |
oct | 240211033143132 |
9 | 42885715375515 |
10 | 11013511235162 |
11 | 3566892a74967 |
12 | 129a5aa7666a2 |
13 | 61b7536b2967 |
14 | 2a10b1b7d2c2 |
15 | 1417479432e2 |
hex | a04486cc65a |
11013511235162 has 4 divisors (see below), whose sum is σ = 16520266852746. Its totient is φ = 5506755617580.
The previous prime is 11013511235149. The next prime is 11013511235183. The reversal of 11013511235162 is 26153211531011.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 9811986143281 + 1201525091881 = 3132409^2 + 1096141^2 .
It is a super-4 number, since 4×110135112351624 (a number of 53 digits) contains 4444 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2753377808789 + ... + 2753377808792.
Almost surely, 211013511235162 is an apocalyptic number.
11013511235162 is a deficient number, since it is larger than the sum of its proper divisors (5506755617584).
11013511235162 is an equidigital number, since it uses as much as digits as its factorization.
11013511235162 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5506755617583.
The product of its (nonzero) digits is 5400, while the sum is 32.
Adding to 11013511235162 its reverse (26153211531011), we get a palindrome (37166722766173).
The spelling of 11013511235162 in words is "eleven trillion, thirteen billion, five hundred eleven million, two hundred thirty-five thousand, one hundred sixty-two".
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