Base | Representation |
---|---|
bin | 10100100000111010… |
… | …11000011110100101 |
3 | 1001102112221121202102 |
4 | 22100131120132211 |
5 | 140023432244013 |
6 | 5020510421445 |
7 | 536632453046 |
oct | 122035303645 |
9 | 31375847672 |
10 | 11013556133 |
11 | 4741957808 |
12 | 2174501885 |
13 | 1066992a28 |
14 | 7669dc8cd |
15 | 446d6ad58 |
hex | 2907587a5 |
11013556133 has 2 divisors, whose sum is σ = 11013556134. Its totient is φ = 11013556132.
The previous prime is 11013556111. The next prime is 11013556153. The reversal of 11013556133 is 33165531011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7696026529 + 3317529604 = 87727^2 + 57598^2 .
It is a cyclic number.
It is not a de Polignac number, because 11013556133 - 214 = 11013539749 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11013556096 and 11013556105.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11013556153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506778066 + 5506778067.
It is an arithmetic number, because the mean of its divisors is an integer number (5506778067).
Almost surely, 211013556133 is an apocalyptic number.
It is an amenable number.
11013556133 is a deficient number, since it is larger than the sum of its proper divisors (1).
11013556133 is an equidigital number, since it uses as much as digits as its factorization.
11013556133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4050, while the sum is 29.
The spelling of 11013556133 in words is "eleven billion, thirteen million, five hundred fifty-six thousand, one hundred thirty-three".
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