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11013655481 is a prime number
BaseRepresentation
bin10100100000111011…
…10000101110111001
31001102120010200000222
422100131300232321
5140023443433411
65020512505425
7536633345513
oct122035605671
931376120028
1011013655481
114741a15414
12217454b275
1310669c900a
14766a26bb3
15446d8a4db
hex290770bb9

11013655481 has 2 divisors, whose sum is σ = 11013655482. Its totient is φ = 11013655480.

The previous prime is 11013655451. The next prime is 11013655487. The reversal of 11013655481 is 18455631011.

11013655481 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10816000000 + 197655481 = 104000^2 + 14059^2 .

It is an emirp because it is prime and its reverse (18455631011) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11013655481 is a prime.

It is a super-2 number, since 2×110136554812 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11013655487) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506827740 + 5506827741.

It is an arithmetic number, because the mean of its divisors is an integer number (5506827741).

Almost surely, 211013655481 is an apocalyptic number.

It is an amenable number.

11013655481 is a deficient number, since it is larger than the sum of its proper divisors (1).

11013655481 is an equidigital number, since it uses as much as digits as its factorization.

11013655481 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14400, while the sum is 35.

The spelling of 11013655481 in words is "eleven billion, thirteen million, six hundred fifty-five thousand, four hundred eighty-one".