Base | Representation |
---|---|
bin | 1010000001000111111000… |
… | …0011100100010010110011 |
3 | 1102222222010020111220022212 |
4 | 2200101332003210102303 |
5 | 2420430003204330001 |
6 | 35231541153322335 |
7 | 2214523241564354 |
oct | 240217603442263 |
9 | 42888106456285 |
10 | 11014411011251 |
11 | 3567204963a6a |
12 | 129a7bbb663ab |
13 | 61b867c2b44b |
14 | 2a115947bd2b |
15 | 14179b9287bb |
hex | a047e0e44b3 |
11014411011251 has 2 divisors, whose sum is σ = 11014411011252. Its totient is φ = 11014411011250.
The previous prime is 11014411011223. The next prime is 11014411011271. The reversal of 11014411011251 is 15211011441011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11014411011251 - 210 = 11014411010227 is a prime.
It is not a weakly prime, because it can be changed into another prime (11014411011271) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5507205505625 + 5507205505626.
It is an arithmetic number, because the mean of its divisors is an integer number (5507205505626).
Almost surely, 211014411011251 is an apocalyptic number.
11014411011251 is a deficient number, since it is larger than the sum of its proper divisors (1).
11014411011251 is an equidigital number, since it uses as much as digits as its factorization.
11014411011251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 160, while the sum is 23.
Adding to 11014411011251 its reverse (15211011441011), we get a palindrome (26225422452262).
The spelling of 11014411011251 in words is "eleven trillion, fourteen billion, four hundred eleven million, eleven thousand, two hundred fifty-one".
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