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110145223151417 is a prime number
BaseRepresentation
bin11001000010110100101110…
…111001100100111100111001
3112102222210001222112020121202
4121002310232321210330321
5103414104404111321132
61030132003355543545
732125505211113546
oct3102645671447471
9472883058466552
10110145223151417
1132106365a972a3
121042aa7045abb5
13495c85acc3c9c
141d2b0b311bbcd
15cb01e3c69762
hex642d2ee64f39

110145223151417 has 2 divisors, whose sum is σ = 110145223151418. Its totient is φ = 110145223151416.

The previous prime is 110145223151323. The next prime is 110145223151419. The reversal of 110145223151417 is 714151322541011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 71461002878521 + 38684220272896 = 8453461^2 + 6219664^2 .

It is a cyclic number.

It is not a de Polignac number, because 110145223151417 - 220 = 110145222102841 is a prime.

Together with 110145223151419, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (110145223151419) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55072611575708 + 55072611575709.

It is an arithmetic number, because the mean of its divisors is an integer number (55072611575709).

Almost surely, 2110145223151417 is an apocalyptic number.

It is an amenable number.

110145223151417 is a deficient number, since it is larger than the sum of its proper divisors (1).

110145223151417 is an equidigital number, since it uses as much as digits as its factorization.

110145223151417 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 33600, while the sum is 38.

Adding to 110145223151417 its reverse (714151322541011), we get a palindrome (824296545692428).

The spelling of 110145223151417 in words is "one hundred ten trillion, one hundred forty-five billion, two hundred twenty-three million, one hundred fifty-one thousand, four hundred seventeen".