Base | Representation |
---|---|
bin | 10100100001001010… |
… | …10111101101000101 |
3 | 1001102200220000011101 |
4 | 22100211113231011 |
5 | 140030001300432 |
6 | 5021023340101 |
7 | 536656324003 |
oct | 122045275505 |
9 | 31380800141 |
10 | 11015650117 |
11 | 4743057a7a |
12 | 2175151631 |
13 | 1067246b84 |
14 | 766dc5a73 |
15 | 4471314e7 |
hex | 290957b45 |
11015650117 has 2 divisors, whose sum is σ = 11015650118. Its totient is φ = 11015650116.
The previous prime is 11015650109. The next prime is 11015650147. The reversal of 11015650117 is 71105651011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10074939876 + 940710241 = 100374^2 + 30671^2 .
It is a cyclic number.
It is not a de Polignac number, because 11015650117 - 23 = 11015650109 is a prime.
It is a super-2 number, since 2×110156501172 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11015650147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5507825058 + 5507825059.
It is an arithmetic number, because the mean of its divisors is an integer number (5507825059).
Almost surely, 211015650117 is an apocalyptic number.
It is an amenable number.
11015650117 is a deficient number, since it is larger than the sum of its proper divisors (1).
11015650117 is an equidigital number, since it uses as much as digits as its factorization.
11015650117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1050, while the sum is 28.
The spelling of 11015650117 in words is "eleven billion, fifteen million, six hundred fifty thousand, one hundred seventeen".
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