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11017057331153 is a prime number
BaseRepresentation
bin1010000001010001101111…
…0010011110011111010001
31110000012221200000212210002
42200110123302132133101
52421000413134044103
635233055525215345
72214645644124626
oct240243362363721
943005850025702
1011017057331153
113568342716305
12129b21a261555
1361bb9a26b703
142a132aada34d
151418a3e08488
hexa051bc9e7d1

11017057331153 has 2 divisors, whose sum is σ = 11017057331154. Its totient is φ = 11017057331152.

The previous prime is 11017057331123. The next prime is 11017057331183. The reversal of 11017057331153 is 35113375071011.

11017057331153 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a balanced prime because it is at equal distance from previous prime (11017057331123) and next prime (11017057331183).

It can be written as a sum of positive squares in only one way, i.e., 9055242511249 + 1961814819904 = 3009193^2 + 1400648^2 .

It is a cyclic number.

It is not a de Polignac number, because 11017057331153 - 222 = 11017053136849 is a prime.

It is not a weakly prime, because it can be changed into another prime (11017057331123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5508528665576 + 5508528665577.

It is an arithmetic number, because the mean of its divisors is an integer number (5508528665577).

Almost surely, 211017057331153 is an apocalyptic number.

It is an amenable number.

11017057331153 is a deficient number, since it is larger than the sum of its proper divisors (1).

11017057331153 is an equidigital number, since it uses as much as digits as its factorization.

11017057331153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 33075, while the sum is 38.

The spelling of 11017057331153 in words is "eleven trillion, seventeen billion, fifty-seven million, three hundred thirty-one thousand, one hundred fifty-three".