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11020050553 is a prime number
BaseRepresentation
bin10100100001101100…
…01010000001111001
31001110000011120102111
422100312022001321
5140032113104203
65021301532321
7540041612161
oct122066120171
931400146374
1011020050553
1147455930a6
1221767140a1
131068127a95
1476780d5a1
1544770026d
hex290d8a079

11020050553 has 2 divisors, whose sum is σ = 11020050554. Its totient is φ = 11020050552.

The previous prime is 11020050551. The next prime is 11020050583. The reversal of 11020050553 is 35505002011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9023480064 + 1996570489 = 94992^2 + 44683^2 .

It is an emirp because it is prime and its reverse (35505002011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11020050553 - 21 = 11020050551 is a prime.

Together with 11020050551, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (11020050551) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5510025276 + 5510025277.

It is an arithmetic number, because the mean of its divisors is an integer number (5510025277).

Almost surely, 211020050553 is an apocalyptic number.

It is an amenable number.

11020050553 is a deficient number, since it is larger than the sum of its proper divisors (1).

11020050553 is an equidigital number, since it uses as much as digits as its factorization.

11020050553 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 750, while the sum is 22.

Adding to 11020050553 its reverse (35505002011), we get a palindrome (46525052564).

The spelling of 11020050553 in words is "eleven billion, twenty million, fifty thousand, five hundred fifty-three".