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1102012001323 = 10910110201847
BaseRepresentation
bin10000000010010101000…
…010001010110000101011
310220100111010000000200021
4100002111002022300223
5121023410033020243
62202131325421311
7142421612312422
oct20022502126053
93810433000607
101102012001323
113953a7055402
121596b170a837
137cbc48950bc
143b4a27a82b9
151d9ec4346ed
hex1009508ac2b

1102012001323 has 4 divisors (see below), whose sum is σ = 1112122203280. Its totient is φ = 1091901799368.

The previous prime is 1102012001317. The next prime is 1102012001327. The reversal of 1102012001323 is 3231002102011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1102012001323 - 233 = 1093422066731 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1102012001297 and 1102012001306.

It is not an unprimeable number, because it can be changed into a prime (1102012001327) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5055100815 + ... + 5055101032.

It is an arithmetic number, because the mean of its divisors is an integer number (278030550820).

Almost surely, 21102012001323 is an apocalyptic number.

1102012001323 is a deficient number, since it is larger than the sum of its proper divisors (10110201957).

1102012001323 is a wasteful number, since it uses less digits than its factorization.

1102012001323 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10110201956.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 1102012001323 its reverse (3231002102011), we get a palindrome (4333014103334).

The spelling of 1102012001323 in words is "one trillion, one hundred two billion, twelve million, one thousand, three hundred twenty-three".

Divisors: 1 109 10110201847 1102012001323