Base | Representation |
---|---|
bin | 10100100001101101… |
… | …00000101001011001 |
3 | 1001110000100021111121 |
4 | 22100312200221121 |
5 | 140032124040233 |
6 | 5021303525241 |
7 | 540042446233 |
oct | 122066405131 |
9 | 31400307447 |
10 | 11020143193 |
11 | 4745646764 |
12 | 2176759821 |
13 | 106815acb7 |
14 | 767835253 |
15 | 44771c92d |
hex | 290da0a59 |
11020143193 has 2 divisors, whose sum is σ = 11020143194. Its totient is φ = 11020143192.
The previous prime is 11020143191. The next prime is 11020143217. The reversal of 11020143193 is 39134102011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9858901264 + 1161241929 = 99292^2 + 34077^2 .
It is an emirp because it is prime and its reverse (39134102011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11020143193 - 21 = 11020143191 is a prime.
Together with 11020143191, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (11020143191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5510071596 + 5510071597.
It is an arithmetic number, because the mean of its divisors is an integer number (5510071597).
Almost surely, 211020143193 is an apocalyptic number.
It is an amenable number.
11020143193 is a deficient number, since it is larger than the sum of its proper divisors (1).
11020143193 is an equidigital number, since it uses as much as digits as its factorization.
11020143193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 25.
The spelling of 11020143193 in words is "eleven billion, twenty million, one hundred forty-three thousand, one hundred ninety-three".
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