Base | Representation |
---|---|
bin | 10000000010010101100… |
… | …100111101011111100011 |
3 | 10220100111202011101220211 |
4 | 100002111210331133203 |
5 | 121023414401401034 |
6 | 2202132253114551 |
7 | 142422052660366 |
oct | 20022544753743 |
9 | 3810452141824 |
10 | 1102021122019 |
11 | 395401214974 |
12 | 1596b4788a57 |
13 | 7cbc673966c |
14 | 3b4a3aa00dd |
15 | 1d9ed136d64 |
hex | 1009593d7e3 |
1102021122019 has 2 divisors, whose sum is σ = 1102021122020. Its totient is φ = 1102021122018.
The previous prime is 1102021121989. The next prime is 1102021122049. The reversal of 1102021122019 is 9102211202011.
It is a balanced prime because it is at equal distance from previous prime (1102021121989) and next prime (1102021122049).
It is an emirp because it is prime and its reverse (9102211202011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1102021122019 - 223 = 1102012733411 is a prime.
It is a super-2 number, since 2×11020211220192 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1102021122049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551010561009 + 551010561010.
It is an arithmetic number, because the mean of its divisors is an integer number (551010561010).
Almost surely, 21102021122019 is an apocalyptic number.
1102021122019 is a deficient number, since it is larger than the sum of its proper divisors (1).
1102021122019 is an equidigital number, since it uses as much as digits as its factorization.
1102021122019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 22.
The spelling of 1102021122019 in words is "one trillion, one hundred two billion, twenty-one million, one hundred twenty-two thousand, nineteen".
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