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1102022200141 is a prime number
BaseRepresentation
bin10000000010010101101…
…001000100101101001101
310220100111211012011211021
4100002111221010231031
5121023420140401031
62202132332154141
7142422065100532
oct20022551045515
93810454164737
101102022200141
11395401890985
121596b5008951
137cbc6a262c5
143b4a3ca0d89
151d9ed29b511
hex10095a44b4d

1102022200141 has 2 divisors, whose sum is σ = 1102022200142. Its totient is φ = 1102022200140.

The previous prime is 1102022200121. The next prime is 1102022200241. The reversal of 1102022200141 is 1410022202011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1045772116900 + 56250083241 = 1022630^2 + 237171^2 .

It is an emirp because it is prime and its reverse (1410022202011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1102022200141 - 215 = 1102022167373 is a prime.

It is a super-2 number, since 2×11020222001412 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1102022200121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551011100070 + 551011100071.

It is an arithmetic number, because the mean of its divisors is an integer number (551011100071).

Almost surely, 21102022200141 is an apocalyptic number.

It is an amenable number.

1102022200141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1102022200141 is an equidigital number, since it uses as much as digits as its factorization.

1102022200141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64, while the sum is 16.

Adding to 1102022200141 its reverse (1410022202011), we get a palindrome (2512044402152).

The spelling of 1102022200141 in words is "one trillion, one hundred two billion, twenty-two million, two hundred thousand, one hundred forty-one".