Base | Representation |
---|---|
bin | 1010000001011111000101… |
… | …1010011001100111111101 |
3 | 1110000120012102222121010112 |
4 | 2200113301122121213331 |
5 | 2421030233141001442 |
6 | 35234451315115405 |
7 | 2215133523542645 |
oct | 240276132314775 |
9 | 43016172877115 |
10 | 11020641343997 |
11 | 356991180519a |
12 | 129ba5a5a2b65 |
13 | 61c31b941a7c |
14 | 2a158aac7525 |
15 | 141a138ad082 |
hex | a05f16999fd |
11020641343997 has 2 divisors, whose sum is σ = 11020641343998. Its totient is φ = 11020641343996.
The previous prime is 11020641343991. The next prime is 11020641344021. The reversal of 11020641343997 is 79934314602011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7382882385316 + 3637758958681 = 2717146^2 + 1907291^2 .
It is a cyclic number.
It is not a de Polignac number, because 11020641343997 - 214 = 11020641327613 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11020641343991) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5510320671998 + 5510320671999.
It is an arithmetic number, because the mean of its divisors is an integer number (5510320671999).
Almost surely, 211020641343997 is an apocalyptic number.
It is an amenable number.
11020641343997 is a deficient number, since it is larger than the sum of its proper divisors (1).
11020641343997 is an equidigital number, since it uses as much as digits as its factorization.
11020641343997 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 979776, while the sum is 50.
The spelling of 11020641343997 in words is "eleven trillion, twenty billion, six hundred forty-one million, three hundred forty-three thousand, nine hundred ninety-seven".
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