110210214113 has 4 divisors (see below), whose sum is σ = 110667518148. Its totient is φ = 109752910080.

The previous prime is 110210214091. The next prime is 110210214133. The reversal of 110210214113 is 311412012011.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 311412012011 = 61 ⋅5105114951.

It can be written as a sum of positive squares in 2 ways, for example, as 57838807009 + 52371407104 = 240497^2 + 228848^2 .

It is a cyclic number.

It is not a de Polignac number, because 110210214113 - 2²⁴ = 110193436897 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 110210214091 and 110210214100.

It is not an unprimeable number, because it can be changed into a prime (110210214133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 228651656 + ... + 228652137.

It is an arithmetic number, because the mean of its divisors is an integer number (27666879537).

Almost surely, 2^110210214113 is an apocalyptic number.

It is an amenable number.

110210214113 is a deficient number, since it is larger than the sum of its proper divisors (457304035).

110210214113 is an equidigital number, since it uses as much as digits as its factorization.

110210214113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 457304034.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 110210214113 its reverse (311412012011), we get a palindrome (421622226124).

The spelling of 110210214113 in words is "one hundred ten billion, two hundred ten million, two hundred fourteen thousand, one hundred thirteen".