Base | Representation |
---|---|
bin | 1010000001100000111000… |
… | …0000111010001101010111 |
3 | 1110000121102212220212011111 |
4 | 2200120032000322031113 |
5 | 2421032224011412413 |
6 | 35235011100115451 |
7 | 2215151441343625 |
oct | 240301600721527 |
9 | 43017385825144 |
10 | 11021121200983 |
11 | 356a038663913 |
12 | 129bb73235b87 |
13 | 61c39719360a |
14 | 2a15d4718515 |
15 | 141a40a97d3d |
hex | a060e03a357 |
11021121200983 has 2 divisors, whose sum is σ = 11021121200984. Its totient is φ = 11021121200982.
The previous prime is 11021121200977. The next prime is 11021121201007. The reversal of 11021121200983 is 38900212112011.
It is a weak prime.
It is an emirp because it is prime and its reverse (38900212112011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11021121200983 - 221 = 11021119103831 is a prime.
It is a super-2 number, since 2×110211212009832 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11021121200923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5510560600491 + 5510560600492.
It is an arithmetic number, because the mean of its divisors is an integer number (5510560600492).
Almost surely, 211021121200983 is an apocalyptic number.
11021121200983 is a deficient number, since it is larger than the sum of its proper divisors (1).
11021121200983 is an equidigital number, since it uses as much as digits as its factorization.
11021121200983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 31.
Adding to 11021121200983 its reverse (38900212112011), we get a palindrome (49921333312994).
The spelling of 11021121200983 in words is "eleven trillion, twenty-one billion, one hundred twenty-one million, two hundred thousand, nine hundred eighty-three".
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