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1102112130022 = 2551056065011
BaseRepresentation
bin10000000010011011000…
…000001000001111100110
310220100202002102002102121
4100002123000020033212
5121024111201130042
62202145303500154
7142424236352011
oct20023300101746
93810662362377
101102112130022
113954486245a2
1215971b15765a
137cc0c552357
143b4b1bd0378
151da06112367
hex1009b0083e6

1102112130022 has 4 divisors (see below), whose sum is σ = 1653168195036. Its totient is φ = 551056065010.

The previous prime is 1102112130013. The next prime is 1102112130071. The reversal of 1102112130022 is 2200312112011.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×11021121300222 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1102112129978 and 1102112130005.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275528032504 + ... + 275528032507.

It is an arithmetic number, because the mean of its divisors is an integer number (413292048759).

Almost surely, 21102112130022 is an apocalyptic number.

1102112130022 is a deficient number, since it is larger than the sum of its proper divisors (551056065014).

1102112130022 is an equidigital number, since it uses as much as digits as its factorization.

1102112130022 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 551056065013.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 1102112130022 its reverse (2200312112011), we get a palindrome (3302424242033).

The spelling of 1102112130022 in words is "one trillion, one hundred two billion, one hundred twelve million, one hundred thirty thousand, twenty-two".

Divisors: 1 2 551056065011 1102112130022