Search a number
-
+
1102112202013 = 4792300860547
BaseRepresentation
bin10000000010011011000…
…000011001110100011101
310220100202002112202011221
4100002123000121310131
5121024111210431023
62202145305213341
7142424240101624
oct20023300316435
93810662482157
101102112202013
11395448673699
1215971b191251
137cc0c579054
143b4b1c0c6bb
151da0612885d
hex1009b019d1d

1102112202013 has 4 divisors (see below), whose sum is σ = 1104413063040. Its totient is φ = 1099811340988.

The previous prime is 1102112201969. The next prime is 1102112202019. The reversal of 1102112202013 is 3102022112011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1102112202013 - 221 = 1102110104861 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1102112202019) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1150429795 + ... + 1150430752.

It is an arithmetic number, because the mean of its divisors is an integer number (276103265760).

Almost surely, 21102112202013 is an apocalyptic number.

It is an amenable number.

1102112202013 is a deficient number, since it is larger than the sum of its proper divisors (2300861027).

1102112202013 is an equidigital number, since it uses as much as digits as its factorization.

1102112202013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2300861026.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 1102112202013 its reverse (3102022112011), we get a palindrome (4204134314024).

The spelling of 1102112202013 in words is "one trillion, one hundred two billion, one hundred twelve million, two hundred two thousand, thirteen".

Divisors: 1 479 2300860547 1102112202013