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11021207 = 21535119
BaseRepresentation
bin101010000010…
…101110010111
3202201221020212
4222002232113
510310134312
61032120035
7162451541
oct52025627
922657225
1011021207
11624843a
12383601b
13238b632
14166c691
15e7a822
hexa82b97

11021207 has 4 divisors (see below), whose sum is σ = 11028480. Its totient is φ = 11013936.

The previous prime is 11021183. The next prime is 11021249. The reversal of 11021207 is 70212011.

11021207 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 11021207 - 28 = 11020951 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11021191 and 11021200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11021407) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 407 + ... + 4712.

It is an arithmetic number, because the mean of its divisors is an integer number (2757120).

Almost surely, 211021207 is an apocalyptic number.

11021207 is a deficient number, since it is larger than the sum of its proper divisors (7273).

11021207 is an equidigital number, since it uses as much as digits as its factorization.

11021207 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7272.

The product of its (nonzero) digits is 28, while the sum is 14.

The square root of 11021207 is about 3319.8203264635. The cubic root of 11021207 is about 222.5408383567.

Adding to 11021207 its reverse (70212011), we get a palindrome (81233218).

The spelling of 11021207 in words is "eleven million, twenty-one thousand, two hundred seven".

Divisors: 1 2153 5119 11021207