Base | Representation |
---|---|
bin | 10000000010011011100… |
… | …010011011000011111001 |
3 | 10220100202201022211100111 |
4 | 100002123202123003321 |
5 | 121024121001314433 |
6 | 2202150224304321 |
7 | 142424405643565 |
oct | 20023342330371 |
9 | 3810681284314 |
10 | 1102121119993 |
11 | 395452704923 |
12 | 1597221720a1 |
13 | 7cc1137c26a |
14 | 3b4b30906a5 |
15 | 1da06cdadcd |
hex | 1009b89b0f9 |
1102121119993 has 2 divisors, whose sum is σ = 1102121119994. Its totient is φ = 1102121119992.
The previous prime is 1102121119973. The next prime is 1102121120017. The reversal of 1102121119993 is 3999111212011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 811786584064 + 290334535929 = 900992^2 + 538827^2 .
It is a cyclic number.
It is not a de Polignac number, because 1102121119993 - 29 = 1102121119481 is a prime.
It is not a weakly prime, because it can be changed into another prime (1102121119973) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551060559996 + 551060559997.
It is an arithmetic number, because the mean of its divisors is an integer number (551060559997).
Almost surely, 21102121119993 is an apocalyptic number.
It is an amenable number.
1102121119993 is a deficient number, since it is larger than the sum of its proper divisors (1).
1102121119993 is an equidigital number, since it uses as much as digits as its factorization.
1102121119993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8748, while the sum is 40.
The spelling of 1102121119993 in words is "one trillion, one hundred two billion, one hundred twenty-one million, one hundred nineteen thousand, nine hundred ninety-three".
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