Base | Representation |
---|---|
bin | 10000000010011011100… |
… | …010011011000100010001 |
3 | 10220100202201022211101101 |
4 | 100002123202123010101 |
5 | 121024121001320032 |
6 | 2202150224304401 |
7 | 142424405643631 |
oct | 20023342330421 |
9 | 3810681284341 |
10 | 1102121120017 |
11 | 395452704945 |
12 | 159722172101 |
13 | 7cc1137c288 |
14 | 3b4b30906c1 |
15 | 1da06cdade7 |
hex | 1009b89b111 |
1102121120017 has 2 divisors, whose sum is σ = 1102121120018. Its totient is φ = 1102121120016.
The previous prime is 1102121119993. The next prime is 1102121120027. The reversal of 1102121120017 is 7100211212011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 757110554641 + 345010565376 = 870121^2 + 587376^2 .
It is a cyclic number.
It is not a de Polignac number, because 1102121120017 - 211 = 1102121117969 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1102121119976 and 1102121120003.
It is not a weakly prime, because it can be changed into another prime (1102121120027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551060560008 + 551060560009.
It is an arithmetic number, because the mean of its divisors is an integer number (551060560009).
Almost surely, 21102121120017 is an apocalyptic number.
It is an amenable number.
1102121120017 is a deficient number, since it is larger than the sum of its proper divisors (1).
1102121120017 is an equidigital number, since it uses as much as digits as its factorization.
1102121120017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 56, while the sum is 19.
Adding to 1102121120017 its reverse (7100211212011), we get a palindrome (8202332332028).
The spelling of 1102121120017 in words is "one trillion, one hundred two billion, one hundred twenty-one million, one hundred twenty thousand, seventeen".
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