Base | Representation |
---|---|
bin | 10100100001110101… |
… | …00111100101110101 |
3 | 1001110002100222220020 |
4 | 22100322213211311 |
5 | 140032413021323 |
6 | 5021342555353 |
7 | 540054553233 |
oct | 122072474565 |
9 | 31402328806 |
10 | 11021220213 |
11 | 4746211963 |
12 | 2176b98b59 |
13 | 10684472a3 |
14 | 767a35953 |
15 | 447881ae3 |
hex | 290ea7975 |
11021220213 has 4 divisors (see below), whose sum is σ = 14694960288. Its totient is φ = 7347480140.
The previous prime is 11021220193. The next prime is 11021220239. The reversal of 11021220213 is 31202212011.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11021220213 - 26 = 11021220149 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11021220192 and 11021220201.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11021220253) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1836870033 + ... + 1836870038.
It is an arithmetic number, because the mean of its divisors is an integer number (3673740072).
Almost surely, 211021220213 is an apocalyptic number.
It is an amenable number.
11021220213 is a deficient number, since it is larger than the sum of its proper divisors (3673740075).
11021220213 is an equidigital number, since it uses as much as digits as its factorization.
11021220213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3673740074.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 11021220213 its reverse (31202212011), we get a palindrome (42223432224).
The spelling of 11021220213 in words is "eleven billion, twenty-one million, two hundred twenty thousand, two hundred thirteen".
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