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11021220213 = 33673740071
BaseRepresentation
bin10100100001110101…
…00111100101110101
31001110002100222220020
422100322213211311
5140032413021323
65021342555353
7540054553233
oct122072474565
931402328806
1011021220213
114746211963
122176b98b59
1310684472a3
14767a35953
15447881ae3
hex290ea7975

11021220213 has 4 divisors (see below), whose sum is σ = 14694960288. Its totient is φ = 7347480140.

The previous prime is 11021220193. The next prime is 11021220239. The reversal of 11021220213 is 31202212011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11021220213 - 26 = 11021220149 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11021220192 and 11021220201.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11021220253) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1836870033 + ... + 1836870038.

It is an arithmetic number, because the mean of its divisors is an integer number (3673740072).

Almost surely, 211021220213 is an apocalyptic number.

It is an amenable number.

11021220213 is a deficient number, since it is larger than the sum of its proper divisors (3673740075).

11021220213 is an equidigital number, since it uses as much as digits as its factorization.

11021220213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3673740074.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 11021220213 its reverse (31202212011), we get a palindrome (42223432224).

The spelling of 11021220213 in words is "eleven billion, twenty-one million, two hundred twenty thousand, two hundred thirteen".

Divisors: 1 3 3673740071 11021220213