Base | Representation |
---|---|
bin | 10000000010011100001… |
… | …111101111011101001001 |
3 | 10220100210112200101200002 |
4 | 100002130033233131021 |
5 | 121024132022000014 |
6 | 2202151331052345 |
7 | 142424611633316 |
oct | 20023417573511 |
9 | 3810715611602 |
10 | 1102133000009 |
11 | 395459389518 |
12 | 1597261410b5 |
13 | 7cc1397b762 |
14 | 3b4b48a3d0d |
15 | 1da07d85dde |
hex | 1009c3ef749 |
1102133000009 has 2 divisors, whose sum is σ = 1102133000010. Its totient is φ = 1102133000008.
The previous prime is 1102132999993. The next prime is 1102133000011. The reversal of 1102133000009 is 9000003312011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 666268960009 + 435864040000 = 816253^2 + 660200^2 .
It is a cyclic number.
It is not a de Polignac number, because 1102133000009 - 24 = 1102132999993 is a prime.
Together with 1102133000011, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1102133005009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551066500004 + 551066500005.
It is an arithmetic number, because the mean of its divisors is an integer number (551066500005).
Almost surely, 21102133000009 is an apocalyptic number.
It is an amenable number.
1102133000009 is a deficient number, since it is larger than the sum of its proper divisors (1).
1102133000009 is an equidigital number, since it uses as much as digits as its factorization.
1102133000009 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 20.
The spelling of 1102133000009 in words is "one trillion, one hundred two billion, one hundred thirty-three million, nine", and thus it is an aban number.
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