11022001122127 has 2 divisors, whose sum is σ = 11022001122128. Its totient is φ = 11022001122126.

The previous prime is 11022001122089. The next prime is 11022001122133. The reversal of 11022001122127 is 72122110022011.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11022001122127 is a prime.

It is a super-3 number, since 3×11022001122127³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11022001122098 and 11022001122107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11022001122137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5511000561063 + 5511000561064.

It is an arithmetic number, because the mean of its divisors is an integer number (5511000561064).

Almost surely, 2^{11022001122127} is an apocalyptic number.

11022001122127 is a deficient number, since it is larger than the sum of its proper divisors (1).

11022001122127 is an equidigital number, since it uses as much as digits as its factorization.

11022001122127 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 224, while the sum is 22.

Adding to 11022001122127 its reverse (72122110022011), we get a palindrome (83144111144138).

The spelling of 11022001122127 in words is "eleven trillion, twenty-two billion, one million, one hundred twenty-two thousand, one hundred twenty-seven".