Base | Representation |
---|---|
bin | 10000000010100010000… |
… | …110011001010100010011 |
3 | 10220101001101111011000112 |
4 | 100002202012121110103 |
5 | 121024332142311311 |
6 | 2202205200111535 |
7 | 142430213504453 |
oct | 20024206312423 |
9 | 3811041434015 |
10 | 1102231213331 |
11 | 3954a986a656 |
12 | 1597530055ab |
13 | 7cc2b117c51 |
14 | 3b4c394bd63 |
15 | 1da117d628b |
hex | 100a2199513 |
1102231213331 has 2 divisors, whose sum is σ = 1102231213332. Its totient is φ = 1102231213330.
The previous prime is 1102231213327. The next prime is 1102231213361. The reversal of 1102231213331 is 1333121322011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1102231213331 - 22 = 1102231213327 is a prime.
It is a super-2 number, since 2×11022312133312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1102231213297 and 1102231213306.
It is not a weakly prime, because it can be changed into another prime (1102231213361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551115606665 + 551115606666.
It is an arithmetic number, because the mean of its divisors is an integer number (551115606666).
Almost surely, 21102231213331 is an apocalyptic number.
1102231213331 is a deficient number, since it is larger than the sum of its proper divisors (1).
1102231213331 is an equidigital number, since it uses as much as digits as its factorization.
1102231213331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 1102231213331 its reverse (1333121322011), we get a palindrome (2435352535342).
The spelling of 1102231213331 in words is "one trillion, one hundred two billion, two hundred thirty-one million, two hundred thirteen thousand, three hundred thirty-one".
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