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11023120302109 is a prime number
BaseRepresentation
bin1010000001101000010100…
…1010111000000000011101
31110000210121012120201100221
42200122011022320000131
52421100322244131414
635235541311521341
72215252124413036
oct240320512700035
943023535521327
1011023120302109
11356a974047103
1212a0430829251
1361c6253b47a6
142a174401ba8d
15141b0b32e224
hexa06852b801d

11023120302109 has 2 divisors, whose sum is σ = 11023120302110. Its totient is φ = 11023120302108.

The previous prime is 11023120302091. The next prime is 11023120302163. The reversal of 11023120302109 is 90120302132011.

Together with previous prime (11023120302091) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10727282214009 + 295838088100 = 3275253^2 + 543910^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11023120302109 is a prime.

It is a super-2 number, since 2×110231203021092 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11023120302179) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5511560151054 + 5511560151055.

It is an arithmetic number, because the mean of its divisors is an integer number (5511560151055).

Almost surely, 211023120302109 is an apocalyptic number.

It is an amenable number.

11023120302109 is a deficient number, since it is larger than the sum of its proper divisors (1).

11023120302109 is an equidigital number, since it uses as much as digits as its factorization.

11023120302109 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 25.

The spelling of 11023120302109 in words is "eleven trillion, twenty-three billion, one hundred twenty million, three hundred two thousand, one hundred nine".